S^2+2s^2=3

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Solution for S^2+2s^2=3 equation: 



^2+2S^2=3

We move all terms to the left:

^2+2S^2-(3)=0

determiningTheFunctionDomain
2S^2-3+^2=0

We add all the numbers together, and all the variables

2S^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$S=\frac{-b}{2a}=\frac{0}{4}=0$

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